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By Nand - Wednesday, May 7, 2008
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The rule I'm trying to define is as follows: If the last character is an "s", "x" or "z" then use the value as is else append an "s". E.g., Alice should become Alices, like in "Alices vader" and Charles should remain unchanged like in "Charles vader". The original (EN) code is: <PossessiveProperNoun T="(s$)=$1' .$)=$1's:" /> which returns Alices and Charles'. But I wanted to get rid of the terminating apostroph. I've tried following combinations but they don't deliver the expected result. T="([sxz]$)=$1[^sxz])=$1s:" returns Aslice and Csharles
T="([sxz]$)=$1.$)=$1s:" returns Alices (OK) and Charless
T="(s$)=$1x$)=$1z$)=$1.$)=$1s:" returns Alices (OK) and Charless Can anybody tell me what I'm doing wrong? PS: I was unable to use script56.chm as documented but found information at http://msdn.microsoft.com/en-us/library/6wzad2b2.aspx
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By jcguasp - Thursday, May 8, 2008
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Try: <PossessiveProperNoun T="([^ sxz]$)=$1s:" /> This code means: if not (the '^') ending (the '$') with s, x or z, append an 's' at the end. I tried it with my tree and it looks OK. JC Update: the script56.chm file can be downloaded at MS: http://www.microsoft.com/downloads/details.aspx?FamilyId=01592C48-207D-4BE1-8A76-1C4099D7BBB9&displaylang=en
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By Nand - Thursday, May 8, 2008
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Thanks JC, your suggestion works. Turns out that I forgot the "$" after "[^sxz]". That's the sort of error you don't see when you wrote it yourself.
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